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K(a) of HA is 10^(-4). The equilibrium c...

`K_(a)` of `HA` is `10^(-4)`. The equilibrium constant for its reaction with a strong base is

A

`1.0 xx 10^(-4)`

B

`1.0 xx 10^(-10)`

C

`1.0 xx 10^(10)`

D

`1.0 xx 10^(14)`

Text Solution

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The correct Answer is:
C
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