When a glycine sol is prepared in NaOH the sol is

Options

A. Positive
B. Neutral
C. Negative
D. Can’t be said

Answer

To determine the charge of a glycine sol prepared in NaOH, we can follow these steps:

### Step 1: Understand the structure of glycine
Glycine is the simplest amino acid with the structure NH2CH2COOH. It has both an amino group (-NH2) and a carboxylic acid group (-COOH).

**Hint:** Recall the functional groups present in glycine and their properties.

### Step 2: Analyze the effect of NaOH on glycine
When NaOH is added to glycine, it acts as a strong base. The hydroxide ions (OH-) from NaOH will interact with the carboxylic acid group of glycine.

**Hint:** Consider how strong bases like NaOH affect acidic groups in amino acids.

### Step 3: Determine the ionization of glycine
In the presence of NaOH, the carboxylic acid group (-COOH) of glycine will lose a proton (H+) and become negatively charged (-COO-). The amino group (-NH2) remains unchanged in this case.

**Hint:** Think about the ionization process of acids in the presence of bases.

### Step 4: Identify the charge of the glycine sol
Since the carboxylate ion (-COO-) is negatively charged and the amino group is neutral, the overall charge of the glycine molecule in this condition becomes negative. Therefore, the glycine sol prepared in NaOH will be negatively charged.

**Hint:** Summarize the charges of the functional groups after the reaction with NaOH.

### Conclusion
When a glycine sol is prepared in NaOH, the sol is negatively charged.

**Final Answer:** The correct answer is that the glycine sol is negatively charged.