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In Zeigler-Natta polymerisation of ethyl...

In Zeigler-Natta polymerisation of ethylene, the active species is

A

`AICI_(3)`

B

`TiCI_(4)`

C

`Et_(3)AI`

D

`Ti^(3+)`

Text Solution

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The correct Answer is:
**Step-by-Step Solution:** 1. **Understanding Ziegler-Natta Polymerization**: Ziegler-Natta polymerization is a method used to synthesize polymers from alkenes, particularly ethylene. It involves the use of a specific type of catalyst known as the Ziegler-Natta catalyst. 2. **Components of Ziegler-Natta Catalyst**: The Ziegler-Natta catalyst consists of two main components: - A transition metal compound (often from group 4 of the periodic table, such as titanium, zirconium, or hafnium). - An organo-aluminum compound, which contains a bond between aluminum and carbon. 3. **Examples of Ziegler-Natta Catalysts**: Common examples of Ziegler-Natta catalysts include: - Titanium tetrachloride (TiCl4) combined with triethylaluminum (Et3Al). - Titanium trichloride (TiCl3) combined with diethylaluminum chloride (AlEt2Cl). 4. **Reaction Mechanism**: In the presence of the Ziegler-Natta catalyst, ethylene (C2H4) molecules undergo polymerization. The catalyst facilitates the reaction by providing an active site for the polymerization process. 5. **Formation of Active Species**: During the polymerization process, the organo-aluminum compound can reduce the titanium compound. For example, triethylaluminum can reduce TiCl4 to TiCl3. The titanium in the TiCl3 state has a +3 oxidation state (Ti^3+), which is the active species in this polymerization process. 6. **Conclusion**: Therefore, the active species in the Ziegler-Natta polymerization of ethylene is titanium in the +3 oxidation state, represented as Ti^3+. **Final Answer**: The active species in Ziegler-Natta polymerization of ethylene is Ti^3+. ---
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