Animals in which development of zygote takes place outside the body of female parent and they lay fertilised/unfertilised eggs are called.

Options

A. Oviparous
B. Viviparous
C. Ovoviviparous
D. Marsupials

Answer

To solve the question, "Animals in which development of zygote takes place outside the body of female parent and they lay fertilised/unfertilised eggs are called," follow these steps:

### Step-by-Step Solution:

1. **Understand the Question**: The question is asking for a specific term that describes animals whose zygote development occurs outside the female parent’s body, and that lay eggs which can be either fertilized or unfertilized.

2. **Identify Key Terms**: The key terms in the question are "development of zygote," "outside the body," "female parent," and "lay fertilized/unfertilized eggs."

3. **Analyze the Options**:
- **Oviparous**: Refers to animals that lay eggs, with the development of the zygote occurring outside the female's body. This includes both fertilized and unfertilized eggs.
- **Viviparous**: Refers to animals that give birth to live young, with the zygote developing inside the female’s body. This is not applicable here.
- **Ooviparous**: This term is not commonly used in standard biological terminology and may be a misinterpretation or confusion with oviparous.
- **Marsupials**: This refers to a group of mammals that give birth to underdeveloped young, which then continue to develop in a pouch. This is also not applicable.

4. **Choose the Correct Answer**: Based on the definitions, the correct term for animals that develop their zygote outside the female's body and lay eggs is **oviparous**.

5. **Provide Examples**: Examples of oviparous animals include birds and reptiles, which lay eggs in a safe environment.

### Final Answer:
The correct answer is **oviparous**.

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