In the given reaction, what is the value of 'x' `N_(2) + 8H^(+) + xATP to 2NH_(3) + H_(2) + xADP + xP_(1)`

Options

A. 8
B. 6
C. 16
D. 2

Answer

To solve the given reaction and find the value of 'x', we will analyze the reaction step by step.

### Step 1: Understand the Reaction
The reaction provided is:
\[ N_2 + 8H^+ + xATP \rightarrow 2NH_3 + H_2 + xADP + xP_1 \]

This reaction represents the process of nitrogen fixation, where nitrogen gas (N2) is converted into ammonia (NH3).

### Step 2: Identify the Components
- **Reactants**: N2, H+, ATP
- **Products**: NH3, H2, ADP, P1 (inorganic phosphate)

### Step 3: Analyze the Reaction Stoichiometry
From the video transcript, we know that the overall reaction for nitrogen fixation can be summarized as:
\[ N_2 + 8H^+ + 16 ATP \rightarrow 2NH_3 + H_2 + 16 ADP + 16 P_1 \]

### Step 4: Compare the Given Reaction to the Known Reaction
Now, we will compare the coefficients of ATP and ADP in the provided reaction with the known reaction:
- In the known reaction, 16 ATP are consumed, which means that 'x' in the given reaction must also equal 16.
- Similarly, since 16 ADP are produced, 'x' must also equal 16 in the products.

### Step 5: Conclusion
Thus, the value of 'x' in the given reaction is:
\[ x = 16 \]

### Final Answer
The value of 'x' is **16**.

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