How many meiotic division are required to form 100 zygotes in family Cyperaceae?

Options

A. 50
B. 300
C. 200
D. 100

Answer

To determine how many meiotic divisions are required to form 100 zygotes in the family Cyperaceae, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Zygote Formation**:
- A zygote is formed when a male gamete (sperm) fertilizes a female gamete (egg).
- Therefore, to form 100 zygotes, we need 100 male gametes and 100 female gametes.

2. **Meiotic Division for Male Gametes**:
- In flowering plants, male gametes are produced from microspores.
- Each microspore is formed through one meiotic division.
- Thus, to produce 100 male gametes, we need 100 meiotic divisions.

3. **Meiotic Division for Female Gametes**:
- Female gametes are produced from megaspores.
- Similar to male gametes, each megaspore is also formed through one meiotic division.
- Therefore, to produce 100 female gametes, we also need 100 meiotic divisions.

4. **Total Meiotic Divisions**:
- Since both male and female gametes require 100 meiotic divisions each, we add these together:
- Total meiotic divisions = 100 (for male gametes) + 100 (for female gametes) = 200 meiotic divisions.

5. **Final Answer**:
- Therefore, the total number of meiotic divisions required to form 100 zygotes in the family Cyperaceae is **200**.