In incomplete linkage, how many types of gametes will be produced
by genotype AaBBCcDd ?

Options

A. 2
B. 4
C. 8
D. 16

Answer

To determine how many types of gametes will be produced by the genotype AaBBCcDd under conditions of incomplete linkage, we can follow these steps:

### Step 1: Identify the Heterozygous Alleles
In the given genotype AaBBCcDd, we need to identify which alleles are heterozygous. The alleles are:
- A (heterozygous: Aa)
- B (homozygous: BB)
- C (heterozygous: Cc)
- D (heterozygous: Dd)

Thus, the heterozygous alleles are A, C, and D.

### Step 2: Count the Number of Heterozygous Alleles
Now, we count the number of heterozygous alleles identified:
- A: 1 (Aa)
- C: 1 (Cc)
- D: 1 (Dd)

Total heterozygous alleles (n) = 3.

### Step 3: Use the Formula to Calculate the Number of Gametes
The number of different types of gametes can be calculated using the formula:
\[ \text{Number of gametes} = 2^n \]
where \( n \) is the number of heterozygous alleles.

Substituting the value of \( n \):
\[ \text{Number of gametes} = 2^3 = 8 \]

### Step 4: Consider the Effect of Incomplete Linkage
In this case, the question specifies that there is incomplete linkage. This means that while the genes are not completely independent, the presence of incomplete linkage does not significantly affect the total number of gametes produced. Therefore, the total number of gametes remains 8.

### Final Answer
The total number of types of gametes produced by the genotype AaBBCcDd is **8**.

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