Home
Class 12
BIOLOGY
In F(2) generation of a Mendelian dihybr...

In `F_(2)` generation of a Mendelian dihybrid cross (w.r.t plant height and flower colour in garden pea), _______ % of the zygote contain heterozygous condition for tallness.

A

25

B

50

C

75

D

`12.5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the percentage of zygotes that contain a heterozygous condition for tallness in the F2 generation of a Mendelian dihybrid cross, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Alleles**: - For plant height, let’s denote the alleles as: - Capital T (T) = tallness (dominant) - Small t (t) = shortness (recessive) - For flower color, we denote: - Capital C (C) = color (dominant) - Small c (c) = color (recessive) 2. **Determine the Parental Genotypes**: - In a dihybrid cross, the parents are typically heterozygous for both traits. Therefore, the parental genotypes will be: - Parent 1: TtCc - Parent 2: TtCc 3. **Gamete Formation**: - Each parent can produce four types of gametes due to independent assortment: - Parent 1 gametes: TC, Tc, tC, tc - Parent 2 gametes: TC, Tc, tC, tc 4. **Construct a Punnett Square**: - Create a 4x4 Punnett square to determine the offspring genotypes by crossing the gametes from both parents. 5. **Fill in the Punnett Square**: - The combinations will yield the following genotypes: - TTCC, TTCc, TtCC, TtCc - TTcc, Ttcc, ttCC, ttCc - TtCc, Ttcc, ttCc, ttcc - (Continue filling in all combinations) 6. **Count the Offspring Genotypes**: - After filling in the Punnett square, count the total number of offspring genotypes that exhibit the heterozygous condition for tallness (Tt). - The genotypes that are heterozygous for tallness (Tt) will be: - TtCC, TtCc (from the first two rows) - TtCc (from the third row) - Count these occurrences. 7. **Calculate the Percentage**: - Total offspring = 16 (4x4 Punnett square) - Count of Tt genotypes = 8 - Percentage of heterozygous tallness = (Number of Tt genotypes / Total Offspring) × 100 - Calculation: (8 / 16) × 100 = 50% ### Final Answer: **50% of the zygotes contain a heterozygous condition for tallness.** ---
Promotional Banner

Topper's Solved these Questions

  • PRINCIPLES OF INHERITANCE AND VARIATIO

    VMC MODULES ENGLISH|Exercise IMPECCABLE|56 Videos
  • PRINCIPLES OF INHERITANCE AND VARIATIO

    VMC MODULES ENGLISH|Exercise ENABLE|49 Videos
  • PLANT KINGDOM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|10 Videos
  • REPRODUCTION IN ORGANISMS

    VMC MODULES ENGLISH|Exercise IMPECCABLE|33 Videos

Similar Questions

Explore conceptually related problems

ln F_(2) generation of a Mendelian dihybrid cross ("TTRR" xx ttrr)

In the F_(2) generation a Mendelian dihybrid cross the number of phenotypes and genotypes are

In the F_(2) generation a Mendelian dihybrid cross the number of phenotypes and genotypes are

In the F_(2) generation a Mendelian dihybrid cross, the number of phenotypes and genotypes are

Mark the odd one (w.r.t. F_(2) generation of Mendelian dihybrid cross)

In a Mendelian dihybrid cross kinds of recombinant phenotypes formed in F_(2) generation

If a cross is made between TtRr x TtRr in garden pea (w.r.t plant height and flower colour), what is the probabilty of the having individuals heterozygous for both traits?

The ratio of F2 generation of a dihybrid cross having pure , monohybrids , dihybrids plants is

How many phenotyes w.r.t. flower colour are possible if heterozygous Lathyrus odoratus for two loci is selfed ?

When a red flower homozygous pea plant is crossed with a white flower plant what colour is produced in F_(1) :-

VMC MODULES ENGLISH-PRINCIPLES OF INHERITANCE AND VARIATIO-EFFICIENT
  1. Mutation which commonly observed in cancer cells is

    Text Solution

    |

  2. Identify in incorrect statements (s) w.r.t Gregor Mendel.

    Text Solution

    |

  3. In F(2) generation of a Mendelian dihybrid cross (w.r.t plant height a...

    Text Solution

    |

  4. Many traits which are not so distinct in their occurrence and are spre...

    Text Solution

    |

  5. Morgan explained linkage on the basis of

    Text Solution

    |

  6. How many non-parental gene combinations were obtained when Morgan cros...

    Text Solution

    |

  7. Choose incorrect for honey bee.

    Text Solution

    |

  8. Thalassemia is controlled by genes preset on chromosome.

    Text Solution

    |

  9. In the given pedigree chart, the trait under study is

    Text Solution

    |

  10. A man suffering from haemophilia, married a normal woman whose father ...

    Text Solution

    |

  11. Select an incorrectly matched pair.

    Text Solution

    |

  12. Identify correct statement w.r.t. fruit fly.

    Text Solution

    |

  13. Mark correct option w.r.t multiple alleles.

    Text Solution

    |

  14. Gene B controls the large size of starch grains, while another form b ...

    Text Solution

    |

  15. What will be the total number of phenotypes and genotypes obtained in ...

    Text Solution

    |

  16. Find odd one out. W.r.t codominance.

    Text Solution

    |

  17. Find out the F(2) phenotypic ratio, when a mulatto individual is cross...

    Text Solution

    |

  18. A heterozygous individual ++ab is crossed to its revessive parent and ...

    Text Solution

    |

  19. Alfred Sturtevant is known for his contribution in

    Text Solution

    |

  20. How many types of gametes will be produced by a genotype AaBbCC if all...

    Text Solution

    |