How many types of gametes will be produced by a genotype AaBbCC if all the genes are showing incomplete linkage ?

Options

A. 4
B. 8
C. 2
D. 6

Answer

To determine how many types of gametes will be produced by the genotype AaBbCC, we can follow these steps:

### Step 1: Identify the Alleles
The genotype provided is AaBbCC. Here, we have:
- A: two alleles (A and a)
- B: two alleles (B and b)
- C: one allele (C)

### Step 2: Count the Types of Alleles
- For the A gene, there are 2 possible alleles (A and a).
- For the B gene, there are also 2 possible alleles (B and b).
- For the C gene, since it is homozygous (CC), there is only 1 possible allele (C).

### Step 3: Calculate the Number of Gametes
To find the total number of different gametes produced, we use the formula:
\[ \text{Number of gametes} = (n_1 + 1)(n_2 + 1)(n_3 + 1) \]
where \( n_1, n_2, n_3 \) are the number of alleles for each gene.

In this case:
- For gene A: \( n_1 = 1 \) (since we have A and a)
- For gene B: \( n_2 = 1 \) (since we have B and b)
- For gene C: \( n_3 = 0 \) (since we have only C)

So we can calculate:
\[ \text{Number of gametes} = (1 + 1)(1 + 1)(0 + 1) = 2 \times 2 \times 1 = 4 \]

### Step 4: Conclusion
Thus, the total number of different types of gametes produced by the genotype AaBbCC, considering incomplete linkage, is **4**.

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