The azeotropic mixture of water and HCl boils at `110^(@)C` when this mixture is simple distilled it is possible to obtain

Options

A. Pure HCl
B. Pure water
C. Pure water as well as HCl
D. Neither HCl nor `water` in their pure states

Answer

To solve the question regarding the azeotropic mixture of water and HCl that boils at 110°C, we need to understand the concept of azeotropes and their behavior during distillation. Here’s a step-by-step solution:

### Step 1: Understand Azeotropic Mixtures
An azeotropic mixture is a mixture of two or more liquids that has a constant boiling point and composition throughout the distillation process. This means that when the mixture is boiled, the vapor produced has the same composition as the liquid mixture.

**Hint:** Remember that azeotropes do not change composition upon boiling.

### Step 2: Identify the Boiling Point
The question states that the azeotropic mixture of water and HCl boils at 110°C. At this temperature, the mixture behaves as a single substance rather than a combination of two different liquids.

**Hint:** Azeotropes boil at a specific temperature, which is different from the boiling points of the individual components.

### Step 3: Distillation Process
When this azeotropic mixture is subjected to simple distillation, it will vaporize at 110°C, producing vapor that has the same composition as the liquid. Therefore, the composition of the vapor will not be richer in either HCl or water.

**Hint:** During distillation of an azeotropic mixture, the vapor retains the same ratio of components as the liquid.

### Step 4: Conclusion on Separation
Since the vapor produced during distillation has the same composition as the liquid, it is impossible to obtain pure HCl or pure water from this mixture. The distillation will yield the same azeotropic mixture again, not allowing for the separation of the components in their pure forms.

**Hint:** Azeotropic mixtures cannot be separated into pure components through simple or fractional distillation.

### Final Answer
Therefore, when the azeotropic mixture of water and HCl is simple distilled, it is possible to obtain neither HCl nor water in their pure state.

**Correct Option:** Neither HCl nor water in their pure state.