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Y g of non-volatile organic substance of...

`Y g` of non-volatile organic substance of molecular mass `M` is dissolved in `250 g` benzene. Molal elevation constant of benzene is `K_(b)`. Elevation in its boiling point is given by:s

A

`(M)/(K_(b)Y)`

B

`(4K_(b)Y)/(M)`

C

`(K_(b)Y)/(4M)`

D

`(K_(b)Y)/(M)`

Text Solution

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The correct Answer is:
To solve the problem of calculating the elevation in boiling point when a non-volatile organic substance is dissolved in benzene, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Elevation in Boiling Point:** The elevation in boiling point (\( \Delta T_b \)) is given by the formula: \[ \Delta T_b = K_b \times \text{molality} \] where \( K_b \) is the molal elevation constant of the solvent (benzene in this case). 2. **Define Molality:** Molality (m) is defined as the number of moles of solute per kilogram of solvent. The formula for molality is: \[ \text{molality} = \frac{\text{number of moles of solute}}{\text{mass of solvent in kg}} \] 3. **Calculate the Number of Moles of Solute:** The number of moles of the solute can be calculated using the formula: \[ \text{number of moles} = \frac{\text{mass of solute (Y g)}}{\text{molar mass (M g/mol)}} \] Therefore, the number of moles of the solute is: \[ \text{number of moles} = \frac{Y}{M} \] 4. **Convert the Mass of Solvent to Kilograms:** The mass of benzene is given as 250 g. To convert this to kilograms: \[ \text{mass of solvent} = 250 \, \text{g} = 0.250 \, \text{kg} \] 5. **Calculate Molality:** Now, substituting the number of moles and the mass of solvent into the molality formula: \[ \text{molality} = \frac{\frac{Y}{M}}{0.250} = \frac{Y}{M \times 0.250} = \frac{Y}{0.250M} \] Simplifying: \[ \text{molality} = \frac{Y}{0.250M} = \frac{4Y}{M} \] 6. **Substitute Molality into the Elevation Formula:** Now substituting the molality back into the elevation in boiling point formula: \[ \Delta T_b = K_b \times \text{molality} = K_b \times \frac{4Y}{M} \] Therefore, the elevation in boiling point is: \[ \Delta T_b = \frac{4K_bY}{M} \] ### Final Answer: The elevation in boiling point is given by: \[ \Delta T_b = \frac{4K_bY}{M} \]
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