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Mole fraction of vapour of A above solut...

Mole fraction of vapour of `A` above solution in mixture of `A` and `B(X_(A) = 0.4)` will be `(P_(A)^(@) = 100mm, P_(B)^(@) = 200 mm)`:

A

0.4

B

0.8

C

0.25

D

None of these

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The correct Answer is:
To solve the problem of finding the mole fraction of vapor of component A above a solution of A and B, we will follow these steps: ### Step 1: Identify Given Values We have the following values provided: - Mole fraction of A in the solution, \( X_A = 0.4 \) - Vapor pressure of pure A, \( P^0_A = 100 \, \text{mm} \) - Vapor pressure of pure B, \( P^0_B = 200 \, \text{mm} \) ### Step 2: Calculate Mole Fraction of B Since the total mole fraction must equal 1, we can calculate the mole fraction of B: \[ X_B = 1 - X_A = 1 - 0.4 = 0.6 \] ### Step 3: Calculate Total Vapor Pressure The total vapor pressure \( P_{total} \) of the solution can be calculated using Raoult's Law: \[ P_{total} = P^0_A \cdot X_A + P^0_B \cdot X_B \] Substituting the values: \[ P_{total} = (100 \, \text{mm} \cdot 0.4) + (200 \, \text{mm} \cdot 0.6) \] Calculating each term: \[ P_{total} = 40 \, \text{mm} + 120 \, \text{mm} = 160 \, \text{mm} \] ### Step 4: Calculate Vapor Pressure of A The vapor pressure of A above the solution can be calculated as: \[ P_A = P^0_A \cdot X_A = 100 \, \text{mm} \cdot 0.4 = 40 \, \text{mm} \] ### Step 5: Calculate Mole Fraction of A in the Vapor The mole fraction of A in the vapor phase \( Y_A \) can be calculated using the formula: \[ Y_A = \frac{P_A}{P_{total}} \] Substituting the values: \[ Y_A = \frac{40 \, \text{mm}}{160 \, \text{mm}} = 0.25 \] ### Conclusion The mole fraction of vapor of A above the solution is \( Y_A = 0.25 \).
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