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A solution containing 3.3 g of a substan...

A solution containing 3.3 g of a substance in 125 g of benzene (b.p. `80^(@)C`) boils at `80.66^(@)C`. IF `K_(b)` for one litre of benzene is `3.28^(@)C`. Then the molecular mass of the substance shall be :

A

127.20 g/mole

B

131.20 g/mole

C

137.12 g/mole

D

142.72 g/mole

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The correct Answer is:
B
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A solution containing 3.3g of a substance in 125g of benzne (b.pt = 80^(@)C ) boils at 80.66^(@)C . If K_(b) for benzene is 3.28 "K kg mol"^(-1) the molecular mass of the substance will be :

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A solution containing 28 g of phosphorus in 315 g CS_(2)(b.p. 46.3^(@)C ) boils at 47.98^(@)C . If K_(b) for CS_(2) is 2.34 K kg mol^(-1) . The formula of phosphorus is (at , mass of P = 31).

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The solution of 2.5 g of a non-volatile substance in 100 g of benzene boiled at a temperature 0.42^(@)C higher than the b.p. of pure benzene. Calculate mol. Wt. of the substance. ( K_(b) of benzene is 2.67 K kg "mole"^(-1) )

(a) A solution containing 0.5g of naphithalene in 50g C Cl_(4) yield a boiling point elevation of 0.4K , while a solution of 0.6g of an unknown solute in the same mass of the solvent gives a boiling point elevation of 0.65K . Find the molar mass of the unknown solute. (b) The boiling point of a solution of 0.1g of a substance in 16g of ether was found to be 0.100^(@)C higher that of pure ether. What is the molecular mass of the substance. K_(b) (ether) =2.16K kg "mol"^(-1)

1.355 g of a substance dissolved in 55 g of CH_(3)COOH produced a depression in the freezing point of 0.618^(@)C . Calculate the molecular weight of the substance (K_(f)=3.85)

On dissolving 0.25 g of a non-volatile substance in 30 mL benzene (density 0.8 g mL^(-1)) , its freezing point decreases by 0.25^(@)C . Calculate the molecular mass of non-volatile substance (K_(f) = 5.1 K kg mol^(-1)) .

The vapour pressure of benzene at 80^(@)C is lowered by 10mm by dissoving 2g of a non-volatile substance in 78g of benzene .The vapour pressure of pure benzene at 80^(@)C is 750mm .The molecular weight of the substance will be:

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