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When 174.5 mg of octa atomic sulphur is ...

When 174.5 mg of octa atomic sulphur is added to 78 g of bromine, the boiling point of bromine is: [Given `K_(b)` for `Br_(2)` is 5.2 K `mol^(-1)` kg and boiling point of pure `Br_(2)` is 332.15K]

A

415.23 K

B

310 K

C

220.92 K

D

332.19 K

Text Solution

Verified by Experts

The correct Answer is:
D
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What will be the boliling point of bromine when 174.5 mg of octa-atomic sulphur is added to 78 g of bromine? k'_(b) for Br_(2) is 5.2 Kmol^(-1) kg and b.pt. of Br_(2) " is " 332.15 K

What will be the boliling point of bromine when 174.5 mg of octa-atomic sulphur is added to 78 g of bromine? k'_(b) for Br_(2) is 5.2 Kmol^(-1) kg and b.pt. of Br_(2) " is " 332.15 K

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