The temperature at which ice will begin ...

The temperature at which ice will begin to separate from a mixture of 20 mass percent of glycol `(C_(2)H_(6)O_(2))` in water, is : [`K_(f)` (water) = 1.86 K kg `mol^(-1)`]

A

280.5 K

B

265. 5K

C

276.5 K

D

269.5 K

Text Solution

Verified by Experts

The correct Answer is:

B

Topper's Solved these Questions

LIQUID SOLUTION
VMC MODULES ENGLISH|Exercise IMPECCABLE|100 Videos
LIQUID SOLUTION
VMC MODULES ENGLISH|Exercise ENABLE|100 Videos
JEE MAIN REVISON TEST-23
VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 1)|25 Videos
LIQUID SOLUTIONS
VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE -L|10 Videos

Similar Questions

Explore conceptually related problems

Calculate the temperature at which a solution containing 54g of glucose, (C_(6)H_(12)O_(6)) in 250g of water will freeze. ( K_(f) for water = 1.86 K mol^(-1) kg)

Calcualte the temperature at which a solution containing 54g of glucose, C_(6)H_(12)O_(6) in 250 g of water will freez.e [K_(f) for water = 1.86 K "mol"^(-1))

What should be the freezing point of aqueous solution containing 17g of C_(2)H(5)OH is 1000g of water ( K_(f) for water = 1.86 deg kg mol^(-1) )?

What would be the freezing point of aqueous solution containing 17 g of C_(2)H_(5)OH in 100 g of water (K_(f) H_(2)O = 1.86 K mol^(-1)kg) :

Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water = 1.86 K mol^(-1) kg )

What do you understand by the term that K_(f) for water is 1.86 K kg mol^(-1) ?

45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

A 10 m solution of urea is cooled to -13.02^(@)C . What amount of urea will separate out if the mass of solution taken is 100 g ? [K_(f)("water") =1.86 Kkg mol^(-1)]

VMC MODULES ENGLISH-LIQUID SOLUTION -EFFICIENT

It has been found that minimum temperature recorded on a hill station ...
Text Solution
|
In winter, the normal temperature in Kullu valley was found to be -11^...
Text Solution
|
The temperature at which ice will begin to separate from a mixture of ...
Text Solution
|
The amount of urea to be dissolved in 500 c.c. of water (K(f) H(2)O = ...
Text Solution
|
The molal boiling point constant of water is 0.53^(@)C. When 2 mole of...
Text Solution
|
The boiling point of an aqueous solution of a non-volatile solute is 1...
Text Solution
|
The freezing point of a solution prepared from 1.25 g of non-electroly...
Text Solution
|
Elevation in boiling point of a solution of non-electrolyte in CCl(4) ...
Text Solution
|
A solution of a non-volatile solute in water has a boiling point of 37...
Text Solution
|
Figure explains elevation in boiling point when a non-volatile solute ...
Text Solution
|
Density of 1M solution of a non-electrolyte C(6)H(12)O(6) is 1.18 g/mL...
Text Solution
|
When a solution w g of urea in 1Kg of water is cooled to -0.372^(@)C,2...
Text Solution
|
The relative decrease in VP of an aqueous glucose dilute solution is f...
Text Solution
|
Glucose is added to 1 litre water to such an extent that (DeltaT(f))/(...
Text Solution
|
A solution containing 4 g of a non-volatile organic solute per 100 mL ...
Text Solution
|
The osmotic pressure of a decimolar solution of glucose at 30^(@)C is ...
Text Solution
|
A solution containing 8.6g per dm^(3) of urea (mol. wt. 60) was found...
Text Solution
|
The osmotic pressure of a solution containing 100 ml of 3.4% solution ...
Text Solution
|
Two solutions each in 100 ml have 4 g glucose and 10 g sucrose respect...
Text Solution
|
5 g of a polymer of molecular mass 50kg mol^(-1) is dissolved in 1dm^(...
Text Solution
|