Correct IUPAC name of alkane obtained in the reaciton of 2-chloropropane + sodium and dry ether

Options

A. 2,3-Dimethyl butane
B. n-Hexane
C. Propene
D. 1-Hexene

Answer

To determine the correct IUPAC name of the alkane obtained from the reaction of 2-chloropropane with sodium in dry ether, let's follow these steps:

### Step 1: Understand the Reaction
2-chloropropane (C3H7Cl) reacts with sodium (Na) in dry ether. This reaction is a Wurtz reaction, which typically results in the coupling of alkyl halides to form alkanes.

### Step 2: Write the Structure of 2-Chloropropane
The structure of 2-chloropropane can be represented as follows:
```
CH3
|
CH
|
Cl
|
CH3
```
This indicates that 2-chloropropane has three carbon atoms (C) and one chlorine (Cl) atom attached to the second carbon.

### Step 3: Determine the Product of the Reaction
When 2-chloropropane reacts with sodium, two molecules of 2-chloropropane will couple together, resulting in the formation of an alkane. The reaction can be summarized as:
\[ 2 \text{C3H7Cl} + 2 \text{Na} \rightarrow \text{C6H14} + 2 \text{NaCl} \]

### Step 4: Identify the Structure of the Product
The product formed is hexane (C6H14). The structure can be represented as:
```
CH3-CH2-CH2-CH2-CH2-CH3
```
This indicates that there are six carbon atoms in a straight chain.

### Step 5: Assign the IUPAC Name
The longest carbon chain in the product is 6 carbons long, which corresponds to the alkane "hexane." Since there are no functional groups or substituents in this case, the IUPAC name of the product is simply "hexane."

### Final Answer
The correct IUPAC name of the alkane obtained from the reaction of 2-chloropropane with sodium in dry ether is **hexane**.

---