`(CH_(3))_(3)CMgBr` on reaction with `D_(2)O` produces `:`

Options

A. `(CH_(3))_(3)`CD
B. `(CH_(3))_(3)`COD
C. `(CD_(3))_(3)`CD
D. `(CD_(3))_(3)`OD

Answer

To solve the question `(CH₃)₃C-MgBr` on reaction with `D₂O` produces, we will follow these steps:

### Step 1: Identify the Grignard Reagent
The given compound `(CH₃)₃C-MgBr` is a Grignard reagent. It consists of a tert-butyl group `(CH₃)₃C-` bonded to magnesium bromide.

### Step 2: Understand the Reaction with D₂O
Grignard reagents react with protic solvents. In this case, `D₂O` (heavy water) is a protic solvent. When a Grignard reagent reacts with a protic solvent, the alkyl group (in this case, the tert-butyl group) will bond with the deuterium (D) from `D₂O`.

### Step 3: Write the Reaction
The general reaction for a Grignard reagent with a protic solvent can be represented as:
\[ R-MgX + H_2O \rightarrow R-H + Mg(OH)X \]

For our specific case with `D₂O`, the reaction will be:
\[ (CH₃)₃C-MgBr + D₂O \rightarrow (CH₃)₃C-D + MgBrOD \]

### Step 4: Identify the Products
From the reaction, we can see that the product formed is `(CH₃)₃C-D` (tert-butyl deuteride) and magnesium bromide deuteroxide `MgBrOD`.

### Final Answer
Thus, the product of the reaction `(CH₃)₃C-MgBr` with `D₂O` is:
\[ (CH₃)₃C-D \]

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