The product obtained by the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal can also be prepared by the following reaction

Options

A. Reduction of ethanal with Na/`C_(2)H_(5)`OH
B. 1-Bromopropane with aqueous KOH
C. Iodoethane with alc. KOH
D. 1-Bromopropane with alc. KOH

Answer

To solve the question, we need to determine which of the given options can produce the same product as the hydrolysis of the adduct formed by the reaction of ethyl magnesium iodide with methanal. The product of this reaction is propanol (C3H8O).

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction involves ethyl magnesium iodide (C2H5MgI) reacting with methanal (HCHO).

2. **Understand the Mechanism**:
Ethyl magnesium iodide acts as a nucleophile due to the presence of the Grignard reagent. It attacks the electrophilic carbon of the carbonyl group in methanal.

3. **Formation of the Adduct**:
The nucleophilic attack leads to the formation of an adduct, which is a magnesium alkoxide intermediate. The structure of the adduct can be represented as:
\[ C2H5C(OH)(C2H5)MgI \]

4. **Hydrolysis of the Adduct**:
Upon hydrolysis, the adduct yields propanol (C3H8O):
\[ C2H5C(OH)(C2H5)MgI + H2O \rightarrow C2H5CH2OH + Mg(OH)I \]

5. **Identify the Product**:
The product obtained from the hydrolysis is propanol (C3H8O), also known as 1-propanol.

6. **Evaluate the Options**:
Now we need to evaluate the provided options to see which one can yield propanol.

- **Option 1**: Reduction of ethanol with sodium → This will yield ethanol, not propanol. **(Incorrect)**
- **Option 2**: One bromopropane with aqueous KOH → This will undergo nucleophilic substitution to yield propanol. **(Correct)**
- **Option 3**: Iodoethane with alkyl KOH → This will lead to elimination and form ethene, not propanol. **(Incorrect)**
- **Option 4**: One bromopropane with alkyl KOH → This will lead to elimination and form propene, not propanol. **(Incorrect)**

7. **Conclusion**:
The correct option that can produce the same product (propanol) as the hydrolysis of the adduct formed from ethyl magnesium iodide and methanal is **Option 2**.

### Final Answer:
The correct answer is **Option 2: One bromopropane with aqueous KOH.**