Methanol on heating with salicylic acid and cond . `H_(2) SO_(4)` gives :

Options

A. Formalin
B. Vinegar
C. Oil of winter green
D. None of these

Answer

To solve the question, "Methanol on heating with salicylic acid and concentrated H2SO4 gives:", we can follow these steps:

### Step 1: Identify the reactants
The reactants in this reaction are:
- Methanol (CH₃OH)
- Salicylic acid (C₇H₆O₃), which has a structure that includes a benzene ring with a hydroxyl (–OH) group and a carboxylic acid (–COOH) group.

### Step 2: Understand the reaction type
When an alcohol (methanol) reacts with a carboxylic acid (salicylic acid) in the presence of an acid catalyst (concentrated H₂SO₄), the reaction typically leads to the formation of an ester through a process called esterification.

### Step 3: Write the reaction
The reaction can be represented as follows:
- Salicylic acid + Methanol → Methyl salicylate (an ester) + Water

The chemical equation can be written as:
\[ \text{C}_7\text{H}_6\text{O}_3 + \text{CH}_3\text{OH} \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_8\text{H}_8\text{O}_3 + \text{H}_2\text{O} \]

### Step 4: Identify the product
The product formed from this reaction is methyl salicylate (C₈H₈O₃), which is also known as "oil of wintergreen." The structure of methyl salicylate includes a benzene ring with a methoxy group (–OCH₃) and a hydroxyl group (–OH).

### Step 5: Conclusion
Based on the above steps, when methanol is heated with salicylic acid in the presence of concentrated H₂SO₄, the product formed is methyl salicylate, commonly referred to as oil of wintergreen.

### Final Answer
The correct answer is: **Oil of wintergreen**.

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