In the sequence of following reactions : `CH_(3) OH overset(HI)to CH_(3) I overset(KCN)to CH_(3) CNoverset("Reduction")toXoverset(HNO_(2))to Y, X ` and Y are respectively

Options

A. `CH_(3) CH_(2) NH_(2) and CH_(3) CH_(2) OH`
B. `CH_(3) CH_(2) NH_(2) and CH_(3) COOH`
C. `CH_(3) CH_(2) OH and CH_(3) CHO`
D. `CH_(3) OCH_(3) and CH_(3) CHO`

Answer

To solve the given sequence of reactions, let's break down each step systematically:

### Step 1: Reaction of Methanol with HI
The first reaction involves methanol (CH₃OH) reacting with hydroiodic acid (HI). In this reaction, the hydroxyl group (OH) from methanol is replaced by iodine (I) from HI, resulting in the formation of methyl iodide (CH₃I).

**Reaction:**
\[ \text{CH}_3\text{OH} + \text{HI} \rightarrow \text{CH}_3\text{I} + \text{H}_2\text{O} \]

### Step 2: Reaction of Methyl Iodide with KCN
Next, methyl iodide (CH₃I) reacts with potassium cyanide (KCN). In this reaction, the iodine atom is replaced by the cyanide group (CN), leading to the formation of methyl cyanide (CH₃CN).

**Reaction:**
\[ \text{CH}_3\text{I} + \text{KCN} \rightarrow \text{CH}_3\text{CN} + \text{KI} \]

### Step 3: Reduction of Methyl Cyanide
The next step involves the reduction of methyl cyanide (CH₃CN). During this reduction, the triple bond between carbon and nitrogen in the cyanide group is converted to a single bond, resulting in the formation of ethylamine (CH₃CH₂NH₂).

**Reaction:**
\[ \text{CH}_3\text{CN} \xrightarrow{\text{Reduction}} \text{CH}_3\text{CH}_2\text{NH}_2 \]

### Step 4: Reaction of Ethylamine with HNO₂
Finally, ethylamine (CH₃CH₂NH₂) reacts with nitrous acid (HNO₂). In this reaction, the amino group (NH₂) is replaced by a hydroxyl group (OH), resulting in the formation of ethanol (CH₃CH₂OH).

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{NH}_2 + \text{HNO}_2 \rightarrow \text{CH}_3\text{CH}_2\text{OH} + \text{N}_2 + \text{H}_2\text{O} \]

### Summary of Products
- **X (after reduction of CH₃CN)**: Ethylamine (CH₃CH₂NH₂)
- **Y (after reaction with HNO₂)**: Ethanol (CH₃CH₂OH)

### Final Answer
Thus, the values of X and Y are:
- **X = CH₃CH₂NH₂ (Ethylamine)**
- **Y = CH₃CH₂OH (Ethanol)**

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