Glycerol on treatment with oxalic acid at 383K forms `,`

Options

A. Allyl alcohol
B. Formic acid
C. Glyceraldehyde
D. Glycerol dioxalate

Answer

To solve the problem of what glycerol forms when treated with oxalic acid at 383K, we can follow these steps:

### Step 1: Understand the Reactants
Glycerol (C3H8O3) is a triol, meaning it has three hydroxyl (-OH) groups. Its structure can be represented as:
- CH2OH
- CH(OH)
- CH2OH

Oxalic acid (C2H2O4) is a dicarboxylic acid with the structure:
- HOOC-COOH

### Step 2: Reaction Between Glycerol and Oxalic Acid
When glycerol reacts with oxalic acid, a condensation reaction occurs. In this reaction, the hydroxyl group from glycerol and a hydrogen atom from oxalic acid combine to form water (H2O). This results in the formation of an ester.

### Step 3: Formation of Glycerol Monooxalate
The reaction can be summarized as follows:
- Glycerol + Oxalic Acid → Glycerol Monooxalate + H2O

The structure of glycerol monooxalate can be represented as:
- CH2OCOOH
- CH(OH)
- CH2OH

### Step 4: Decarboxylation
The glycerol monooxalate can undergo decarboxylation, where one of the carboxyl groups (COOH) is removed as carbon dioxide (CO2). This leads to the formation of glycerol monoformate.

### Step 5: Hydrolysis
Upon hydrolysis of glycerol monoformate, the compound breaks down into glycerol and formic acid (HCOOH). The reaction can be summarized as:
- Glycerol Monoformate + H2O → Glycerol + Formic Acid

### Final Product
Thus, when glycerol is treated with oxalic acid at 383K, the final products are:
- Glycerol and Formic Acid

### Conclusion
The correct answer to the question is that glycerol on treatment with oxalic acid at 383K forms **formic acid**.

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