The products formed when diethyl ether is reacted with cold HI are `:`

Options

A. `C_(2)H_(5) I`
B. `C_(2) H_(5) I + C_(2) H_(5) OH`
C. `C_(2) H_(5) I + C_(2) H_(6)`
D. `C_(2)H_(5)I+H_(2)O`

Answer

To determine the products formed when diethyl ether reacts with cold hydrogen iodide (HI), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Diethyl Ether**:
- Diethyl ether has the molecular formula \( \text{C}_4\text{H}_{10}\text{O} \) and can be represented as \( \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \).

2. **Understand the Reaction with HI**:
- When diethyl ether reacts with cold HI, it dissociates into \( \text{H}^+ \) and \( \text{I}^- \) ions.

3. **Protonation of the Ether**:
- The lone pair of electrons on the oxygen atom of diethyl ether attacks the proton (\( \text{H}^+ \)) from hydrogen iodide, leading to the formation of a protonated ether.

4. **Formation of Carbocation**:
- The protonation of the ether makes the oxygen positively charged, which weakens the C-O bond. This results in the formation of a carbocation.

5. **Nucleophilic Attack by Iodide Ion**:
- The iodide ion (\( \text{I}^- \)), being a good nucleophile, attacks the carbocation formed in the previous step, resulting in the formation of ethyl iodide (\( \text{CH}_3\text{CH}_2\text{I} \)).

6. **Formation of Ethyl Alcohol**:
- In addition to ethyl iodide, the reaction also produces ethyl alcohol (\( \text{CH}_3\text{CH}_2\text{OH} \)) as a product from the protonation of one of the ethyl groups.

7. **Final Products**:
- Therefore, the final products of the reaction between diethyl ether and cold HI are ethyl iodide and ethyl alcohol.

### Conclusion:
The products formed when diethyl ether is reacted with cold HI are ethyl iodide and ethyl alcohol.