Alcohol are stronger acids than alkanes. This is clear from the reaction

Options

A. `2ROH + 2 Na to 2RO^(-)Na^(+)+H_(2)`
B. `ROH +R' MgX to R'H +RO -MgX`
C. `ROH +R'COOHto R'COOR+H_(2)O`
D. `ROH +R' COCl to R' COOR +H_(2)O`

Answer

To demonstrate that alcohols are stronger acids than alkanes, we can analyze the following reaction:

1. **Identify the Reaction**: Consider the reaction between an alcohol (ROH) and a Grignard reagent (R'MgX). The reaction can be represented as:
\[ ROH + R'MgX \rightarrow R'H + ROMgX \]

2. **Understanding the Products**: In this reaction, the alcohol (ROH) donates a proton (H⁺) to the Grignard reagent (R'MgX), resulting in the formation of an alkane (R'H) and an alkoxide (ROMgX).

3. **Direction of the Reaction**: The forward direction of the reaction indicates that the alcohol is acting as an acid by donating a proton. If alkanes were stronger acids than alcohols, the reaction would favor the reverse direction, where the alkane would donate a proton instead.

4. **Conclusion on Acidity**: Since the reaction proceeds in the forward direction, it suggests that alcohols are indeed stronger acids than alkanes. If alkanes were stronger acids, the reaction would not proceed forward as observed.

5. **Final Statement**: Therefore, we can conclude that alcohols are stronger acids than alkanes based on the reaction involving both substances.