Which of the following is obtained when `C_(2) H_(5) OC_(2) H_(5)` is heated with conc . `H_(2)SO_(4)` ?

Options

A. `CH_(2) = CH_(2)`
B. `C_(2) H_(5) OH`
C. `C_(2) H_(5) SO_(4)H`
D. `CH_(3) CH_(2) CH_(2) CH_(3)`

Answer

To solve the question of what is obtained when diethyl ether (C2H5OC2H5) is heated with concentrated sulfuric acid (H2SO4), we can follow these steps:

### Step 1: Identify the Reactants
The reactant in this case is diethyl ether, which has the chemical formula C2H5OC2H5.

### Step 2: Understand the Reaction Conditions
The reaction occurs when diethyl ether is heated with concentrated sulfuric acid (H2SO4). Concentrated sulfuric acid is a strong acid and can protonate ethers.

### Step 3: Protonation of Diethyl Ether
When diethyl ether is treated with concentrated sulfuric acid, the ether oxygen atom gets protonated. This creates a positively charged intermediate (a carbocation) as the ether bond breaks.

### Step 4: Formation of Ethyl Hydrogen Sulfate
The protonated ether can then lead to the formation of ethyl hydrogen sulfate (C2H5HSO4) as the carbocation reacts with the bisulfate ion (HSO4-), which acts as a nucleophile. This results in the formation of two moles of ethyl hydrogen sulfate.

### Step 5: Overall Reaction
The overall reaction can be summarized as:
\[ C2H5OC2H5 + H2SO4 \rightarrow 2 C2H5HSO4 + H2O \]

### Step 6: Conclusion
From the reaction, we can conclude that the products formed are two moles of ethyl hydrogen sulfate (C2H5HSO4) and water (H2O).

### Final Answer
The correct answer is that when diethyl ether is heated with concentrated sulfuric acid, it produces 2 moles of ethyl hydrogen sulfate (C2H5HSO4) and water.

---