Outer electronic configuration of an element is 4s13d10. The element is expected to be

Options

A. a metal
B. a non-metal
C. an element of 10th group
D. liquid at `2981^@ C`

Answer

To determine the identity of the element with the outer electronic configuration of 4s¹3d¹⁰, we can follow these steps:

### Step 1: Analyze the given electronic configuration
The outer electronic configuration is given as 4s¹3d¹⁰. This indicates that there is one electron in the 4s subshell and ten electrons in the 3d subshell.

### Step 2: Identify the total number of electrons
To find the total number of electrons, we can add the electrons from the outer configuration to the electrons from the inner shells. The configuration can be expanded as follows:
- The 4s subshell contributes 1 electron.
- The 3d subshell contributes 10 electrons.
- The inner shells (up to Argon) contribute 18 electrons (1s² 2s² 2p⁶ 3s² 3p⁶).

Total electrons = 18 (from Argon) + 1 (from 4s) + 10 (from 3d) = 29 electrons.

### Step 3: Determine the atomic number
The total number of electrons in a neutral atom is equal to the atomic number. Therefore, the atomic number of this element is 29.

### Step 4: Identify the element
Using the periodic table, we can identify the element with atomic number 29. This element is Copper (Cu).

### Step 5: Classify the element
Copper is found in Group 11 of the periodic table and is classified as a transition metal.

### Conclusion
The element with the outer electronic configuration of 4s¹3d¹⁰ is Copper (Cu), which is a transition metal.

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