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1 mole of heptane (Pure V.P. = 92 mm of ...

1 mole of heptane (Pure V.P. = 92 mm of Hg) was mixed with 4 moles of octane (Pure V.P. = 31 mm of Hg). The vapour pressure of resulting ideal solution is:

A

46.2 mm of Hg

B

40.0 mm of Hg

C

43.2 mm of Hg

D

38.4 mm of Hg

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The correct Answer is:
C
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