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The weight of solute (MW-60) required to...

The weight of solute (MW-60) required to be added in 180 g of water to reduce the vapour pressure to 4/5th of pure water is :

A

130 g

B

150 g

C

300 g

D

75 g

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The correct Answer is:
B
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What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to 4//5^(th) of pure water ?

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At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea =60 g "mol"^(-1) )

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