Twenty grams of a solute are added to 10...

Twenty grams of a solute are added to `100g` of water at `25^(@)C`. The vapour pressure of pure water is `23.76 mmHg`, the vapour pressure of the solution is `22.41` Torr.
(a) Calculate the molar mass of the solute.
(b) What mass of this solute is required in `100g` of water of reduce the vapour pressure ot one-half the value for pure water?

A

333 g

B

666 g

C

166 g

D

256 g

Text Solution

Verified by Experts

The correct Answer is:

A

Promotional Banner

Promotional Banner

Topper's Solved these Questions

LIQUID SOLUTION
VMC MODULES ENGLISH|Exercise IMPECCABLE|100 Videos
LIQUID SOLUTION
VMC MODULES ENGLISH|Exercise ENABLE|100 Videos
JEE MAIN REVISON TEST-23
VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 1)|25 Videos
LIQUID SOLUTIONS
VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE -L|10 Videos

Similar Questions

Explore conceptually related problems

At 25^(@)C , the vapour pressure of pure water is 25.0 mm Hg . And that of an aqueous dilute solution of urea is 20 mm Hg . Calculate the molality of the solution.

What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to 4//5^(th) of pure water ?

What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to 4//5^(th) of pure water ?

6.0 g of urea (molecular mass = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :

What mass of non-volatile solute, sucrose, need to be dissolved in 100g of water to decrease the vapour pressure of water by 30%?

The vapour pressure of water is 12.3 kPa at 300 K . Calculate vapour pressure of 1 molal solution of a solute in it.

Vapour pressure of pure water at 23^@C is 19.8 torr . Calculate the vapour of 3m aqueous solution.

The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to

How many grams of sucrose must be added to 360g of water to lower the vapour pressure by 1.19mm Hg at a temperatue at which vapour pressure of pure water is 25 mmHg ?

If common salt is dissolved in water, the vapour pressure of the solution will

VMC MODULES ENGLISH-LIQUID SOLUTION -EFFICIENT

The molality of a solution containing a non-volatile solute if the vap...
Text Solution
|
Calculate the mass of a non-volatile solute (molar mass 40 g mol^(-1))...
Text Solution
|
Twenty grams of a solute are added to 100g of water at 25^(@)C. The va...
Text Solution
|
Vapour pressure of pure water is 40 mm. If a non-volatile solute is ad...
Text Solution
|
The vapour pressure of pure liquid solvent A is 0.80 atm. When a non-v...
Text Solution
|
The vapour pressure of C Cl4 at 25^@C is 143 mm Hg. If 0.5 gm of a non...
Text Solution
|
Lowering of vapour pressure of 1.00 m solution of a non-volatile solut...
Text Solution
|
The vapour pressure of a liquid decreases by 10 torr when a non-volati...
Text Solution
|
The mole fraction of the solvent in the solution of a non-volatile sol...
Text Solution
|
The vapour pressure of a solution of a non-volatile electrolyte B in a...
Text Solution
|
The vapour pressure of water at room temperature is 23.8 mm Hg. The va...
Text Solution
|
The vapour pressure of pure liquid A is 10 torr at at the same tempera...
Text Solution
|
The vapour pressure of pure benzene C(6)H(6) at 50^(@)C is 268 "torr"....
Text Solution
|
The lowering of vapour pressure due to a solute in a 1 m aqueous solut...
Text Solution
|
How many grams of sucrose must be added to 360 g of water to lower the...
Text Solution
|
A solution containing 0.52 g of C(10)H(8) in 50g CCl(4) produced an el...
Text Solution
|
0.65 g naphthalene (C(10)H(8)) was dissolved in 100 g methyl acetate. ...
Text Solution
|
What will be the boliling point of bromine when 174.5 mg of octa-atomi...
Text Solution
|
4.0g of substance A dissolved in 100g H(2)O depressed the freezing poi...
Text Solution
|
An aqueous solution contains 5% by weight of urea and 10% by weight of...
Text Solution
|