Home
Class 12
CHEMISTRY
Vapour pressure of pure water is 40 mm. ...

Vapour pressure of pure water is 40 mm. If a non-volatile solute is added to it vapour pressure falls by 4 mm. Hence, molality of solution is:

A

6.173 molal

B

3.0864 molal

C

1.543 molal

D

0.772 molal

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • LIQUID SOLUTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|100 Videos

  • LIQUID SOLUTION

    VMC MODULES ENGLISH|Exercise ENABLE|100 Videos

  • JEE MAIN REVISON TEST-23

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 1)|25 Videos

  • LIQUID SOLUTIONS

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE -L|10 Videos

Similar Questions

Explore conceptually related problems

Why vapour pressure of a liquid decreases when a non - volatile solute is added to it ?

V.P. of solvent in pure state is 600 mm Hg, when a non-volatile solute is added to it vapour pressure of solution becomes 594 mm Hg, then x_(B) will be

The vapour pressure of pure liquid A is 0.80 atm. On mixing a non-volatile B to A, its vapour pressure becomes 0.6 atm. The mole fraction of B in the solution is:

At 25^(@)C , the vapour pressure of pure water is 25.0 mm Hg . And that of an aqueous dilute solution of urea is 20 mm Hg . Calculate the molality of the solution.

The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute is 0.2 , what would be the mole fraction of solvent if the decrease in vapour pressure is 20 mm of Hg .

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

Vapour pressure of benzene at 30^(@)C is 121.8 mm. When 15 g of a non-volatile solute is dissolved in 250 g of benzene its vapour pressure decreased to 120.2 mm. The molecular weight of the solute is (mol. Weight of solvent = 78)

The vapour pressure of a pure liquid at 25^(@)C is 100 mm Hg. Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.

An ideal solution was found to have a vapour pressure of 80 torr when the mole fraction of a non-volatile solute was 0.2. What would be the vapour pressure of the pure solvent at the same temperature?

VMC MODULES ENGLISH-LIQUID SOLUTION -EFFICIENT
  1. Calculate the mass of a non-volatile solute (molar mass 40 g mol^(-1))...

    Text Solution

    |

  2. Twenty grams of a solute are added to 100g of water at 25^(@)C. The va...

    Text Solution

    |

  3. Vapour pressure of pure water is 40 mm. If a non-volatile solute is ad...

    Text Solution

    |

  4. The vapour pressure of pure liquid solvent A is 0.80 atm. When a non-v...

    Text Solution

    |

  5. The vapour pressure of C Cl4 at 25^@C is 143 mm Hg. If 0.5 gm of a non...

    Text Solution

    |

  6. Lowering of vapour pressure of 1.00 m solution of a non-volatile solut...

    Text Solution

    |

  7. The vapour pressure of a liquid decreases by 10 torr when a non-volati...

    Text Solution

    |

  8. The mole fraction of the solvent in the solution of a non-volatile sol...

    Text Solution

    |

  9. The vapour pressure of a solution of a non-volatile electrolyte B in a...

    Text Solution

    |

  10. The vapour pressure of water at room temperature is 23.8 mm Hg. The va...

    Text Solution

    |

  11. The vapour pressure of pure liquid A is 10 torr at at the same tempera...

    Text Solution

    |

  12. The vapour pressure of pure benzene C(6)H(6) at 50^(@)C is 268 "torr"....

    Text Solution

    |

  13. The lowering of vapour pressure due to a solute in a 1 m aqueous solut...

    Text Solution

    |

  14. How many grams of sucrose must be added to 360 g of water to lower the...

    Text Solution

    |

  15. A solution containing 0.52 g of C(10)H(8) in 50g CCl(4) produced an el...

    Text Solution

    |

  16. 0.65 g naphthalene (C(10)H(8)) was dissolved in 100 g methyl acetate. ...

    Text Solution

    |

  17. What will be the boliling point of bromine when 174.5 mg of octa-atomi...

    Text Solution

    |

  18. 4.0g of substance A dissolved in 100g H(2)O depressed the freezing poi...

    Text Solution

    |

  19. An aqueous solution contains 5% by weight of urea and 10% by weight of...

    Text Solution

    |

  20. The amount of ice that will separate out from a solution containing 25...

    Text Solution

    |