Addition of borane to 1-butene following by oxidative alkaline hydrolysis gives :

Options

A. n-butyl alcohol
B. Sec. butyl alcohol
C. isobutyl alcohol
D. ter. Butyl alcohol

Answer

To solve the question regarding the addition of borane to 1-butene followed by oxidative alkaline hydrolysis, we will follow these steps:

### Step 1: Understand the Hydroboration-Oxidation Reaction
The reaction involves two main steps: hydroboration and oxidation. In the hydroboration step, borane (BH3) adds to the alkene (1-butene) in a syn-addition manner, meaning that both the boron atom and hydrogen add to the same side of the double bond.

### Step 2: Structure of 1-Butene
1-butene has the structure:
\[ \text{CH}_3-\text{CH}_2-\text{CH}=\text{CH}_2 \]

### Step 3: Hydroboration Step
During hydroboration, borane (BH3) adds to the less substituted carbon of the alkene (the terminal carbon in 1-butene). The reaction can be represented as:
\[ \text{CH}_3-\text{CH}_2-\text{CH}=\text{CH}_2 + BH_3 \rightarrow \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2B \]

### Step 4: Further Hydroboration
Since we have one mole of 1-butene, we need to add another mole of borane to fully convert the double bond. This results in:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2B \]

### Step 5: Oxidative Hydrolysis
The next step involves oxidative hydrolysis where the alkyl borane reacts with hydrogen peroxide (H2O2) in the presence of sodium hydroxide (NaOH). This converts the boron atom into a hydroxyl group (-OH):
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2B + H_2O_2 + NaOH \rightarrow \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2OH \]

### Step 6: Product Formation
The final product of this reaction is n-butyl alcohol (1-butanol):
\[ \text{n-Butyl alcohol} = \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2OH \]

### Conclusion
Thus, the addition of borane to 1-butene followed by oxidative alkaline hydrolysis gives n-butyl alcohol.

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