An element has outer shell configuration of `5f^0 6d^2 7s^2`. This element will lie in the

Options

A. s-block
B. p-block
C. d-block
D. f-block

Answer

To determine the block in which the element with the outer shell configuration of `5f^0 6d^2 7s^2` lies, we can follow these steps:

### Step 1: Identify the outer shell configuration
The given outer shell configuration is `5f^0 6d^2 7s^2`. This indicates that the element has electrons in the 6d and 7s orbitals, but no electrons in the 5f orbital.

### Step 2: Determine the principal quantum number (n)
In the configuration `5f^0 6d^2 7s^2`, the highest principal quantum number is 7 (from the 7s orbital). This indicates that the element is in the 7th period of the periodic table.

### Step 3: Identify the type of block
The periodic table is divided into four blocks based on the subshells that are being filled:
- **s-block**: Groups 1 and 2 (and Helium)
- **p-block**: Groups 13 to 18
- **d-block**: Transition metals (Groups 3 to 12)
- **f-block**: Lanthanides and actinides

Since the element has electrons in the 6d subshell, it indicates that it is part of the d-block elements. However, we also need to consider the 5f subshell.

### Step 4: Confirm the block
The presence of `5f^0` indicates that the f-block is not filled, but the element is still associated with the f-block elements because it is in the same period as the actinides. The 6d electrons suggest that it is a transition metal, but since it is in the 7th period and has an empty 5f subshell, it is classified as an f-block element.

### Conclusion
Thus, the element with the outer shell configuration of `5f^0 6d^2 7s^2` lies in the **f-block** of the periodic table.

### Final Answer
The element will lie in the **F block**.

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