If a turgid plant cell (cell with positive turgor pressure) is placed in a hypertonic solution

Options

A. It exerts a higher osmotic pressure
B. Water will move out of the cell by osmosis
C. Cause vacuole and protoplast to shrink
D. All of these

Answer

**Step-by-Step Solution:**

1. **Understanding Turgidity:**
- A turgid plant cell is one that is filled with water, resulting in positive turgor pressure. This pressure helps maintain the cell's shape and firmness.

2. **Defining Hypertonic Solution:**
- A hypertonic solution is one that has a higher concentration of solutes compared to the inside of the cell. This means that the concentration of water is lower outside the cell.

3. **Osmosis Process:**
- Osmosis is the movement of water molecules from an area of lower solute concentration (inside the cell) to an area of higher solute concentration (outside the cell) through a semi-permeable membrane.

4. **Effects on the Turgid Cell:**
- When a turgid plant cell is placed in a hypertonic solution, water will move out of the cell into the surrounding solution. This occurs because the outside solution has a higher concentration of solutes, creating a gradient that drives water out.

5. **Consequences of Water Loss:**
- As water leaves the cell, the vacuole (which stores water) and the protoplast (the living part of the cell) will begin to shrink. This leads to a loss of turgidity, and the cell may become flaccid or even plasmolyzed.

6. **Conclusion:**
- Therefore, when a turgid plant cell is placed in a hypertonic solution, the following occurs:
- It exerts higher osmotic pressure.
- Water moves out of the cell by osmosis.
- The vacuole and protoplast shrink.
- All of these statements are correct, making the final answer: "All of these."

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