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A cell placed in a strong salt solution,...

A cell placed in a strong salt solution, will shrink because

A

A. The cytoplasm will decompose

B

B. Mineral salts will break the cell wall

C

C. Salt will leave the cell

D

D.  Water will leave by exosmosis

Text Solution

AI Generated Solution

The correct Answer is:
To understand why a cell placed in a strong salt solution will shrink, we can break down the process step by step. ### Step-by-Step Solution: 1. **Understanding Osmosis**: Osmosis is the movement of water across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. 2. **Cell in Salt Solution**: When a cell is placed in a strong salt solution, the concentration of solutes (salt) outside the cell is higher than the concentration of solutes inside the cell. 3. **Water Movement**: Due to osmosis, water will move out of the cell (where the solute concentration is lower) into the salt solution (where the solute concentration is higher). 4. **Result of Water Loss**: As water leaves the cell, the volume of the cytoplasm decreases, causing the cell to shrink. This process is known as exosmosis. 5. **Final Outcome**: The cell becomes flaccid or plasmolyzed, which means it has lost turgor pressure and appears shriveled. ### Conclusion: The correct answer to the question is that the cell shrinks because water leaves the cell due to osmosis in response to the high concentration of salt outside the cell.
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Statement-1 : When a cell is placed in hypertonic solution, it shrinks. Statement : 2 Reverse osmosis is used for desalination of water.

Knowledge Check

  • A cell placed in a hypertonic salt solution will shrink because

    A
    water will move from the salt solution to the cell sap
    B
    water will move from the cell sap to the salt solution
    C
    cytoplasm decomposes
    D
    mineral salts break the cell wall
  • A cell placed in hypertonic solution will :

    A
    Shrink
    B
    Show exosmosis
    C
    Show endosmosis
    D
    No change in size and shape
  • A red blood cell placed in 50% NaCl solution will :

    A
    undergo crenation
    B
    swell and eventually burst due to water intake
    C
    stay the same size
    D
    none of the above
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