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If a population of 50 Paramecium present...

If a population of 50 Paramecium present in a pool increases to 150 after an hour, what would be the growth rate of population ?

A

150/ hour

B

200 / hour

C

5 / hour

D

100 / hour

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The correct Answer is:
To find the growth rate of the Paramecium population, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Initial and Final Population**: - The initial population (at time \( t_1 \)) is given as 50 Paramecium. - The final population (after 1 hour, at time \( t_2 \)) is given as 150 Paramecium. 2. **Use the Growth Rate Formula**: - The growth rate can be calculated using the formula: \[ \text{Growth Rate} = \text{Population at } t_2 - \text{Population at } t_1 \] 3. **Substitute the Values**: - Substitute the values into the formula: \[ \text{Growth Rate} = 150 - 50 \] 4. **Calculate the Growth Rate**: - Perform the subtraction: \[ \text{Growth Rate} = 100 \text{ Paramecium per hour} \] 5. **Conclusion**: - The growth rate of the Paramecium population is 100 Paramecium per hour.

To find the growth rate of the Paramecium population, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Initial and Final Population**: - The initial population (at time \( t_1 \)) is given as 50 Paramecium. - The final population (after 1 hour, at time \( t_2 \)) is given as 150 Paramecium. ...
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