A `5-0cm^(3)` solutions of `H_(2)O_(2)` liberates of 0.508g of iodine from acidified KI solution. Calculate the volume strength of `H_(2)O_(2)` at N.T.P.

Explanation

To solve the problem, we need to calculate the volume strength of hydrogen peroxide (H₂O₂) based on the amount of iodine (I₂) liberated from an acidified potassium iodide (KI) solution. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Reaction
The reaction between hydrogen peroxide (H₂O₂) and potassium iodide (KI) in the presence of sulfuric acid (H₂SO₄) can be represented as:
\[ 2 \text{H}_2\text{O}_2 + 2 \text{KI} + \text{H}_2\text{SO}_4 \rightarrow \text{K}_2\text{SO}_4 + 2 \text{H}_2\text{O} + \text{I}_2 \]
From this reaction, we can see that 2 moles of H₂O₂ liberate 1 mole of I₂.
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