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0.45g of an acid of mol. Mass 90 was neu...

`0.45g` of an acid of mol. Mass 90 was neutralised by `20mL` of `0.54 N` caustic potash `(KOH)`. The basicity of acid is :

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
`N_(1)V_(1)=N_(2)V_(2)`
`(0.45xxnxx1000)/(90)=0.5xx20 or n = 2`
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