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Myoglobin stores oxygen for metabolic pr...

Myoglobin stores oxygen for metabolic processes in muscle. Chemical analysis shows that it contains `0.34%` Fe by mass. Minimum molecular mass of myoglobin is

A

16470 gm

B

16176 gm

C

17500 gm

D

1647 gm

Text Solution

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The correct Answer is:
To find the minimum molecular mass of myoglobin based on the given percentage of iron, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information:** - Myoglobin contains `0.34%` iron by mass. - We need to find the minimum molecular mass of myoglobin. 2. **Set Up the Equation:** - Let the minimum molecular mass of myoglobin be represented as `X` grams. - Since `0.34%` of myoglobin is iron, in `100 grams` of myoglobin, there will be `0.34 grams` of iron. 3. **Calculate the Amount of Iron in X grams of Myoglobin:** - In `X grams` of myoglobin, the amount of iron can be calculated as: \[ \text{Amount of Iron} = \frac{0.34}{100} \times X \text{ grams} \] 4. **Use the Molar Mass of Iron:** - The molar mass of iron (Fe) is `56 grams/mol`. - According to the information, the amount of iron in myoglobin can also be expressed in terms of moles: \[ \text{Moles of Iron} = \frac{\text{mass of iron}}{\text{molar mass of iron}} = \frac{\frac{0.34}{100} \times X}{56} \] 5. **Set Up the Equation:** - The moles of iron in myoglobin must equal the mass of iron divided by its molar mass: \[ \frac{0.34}{100} \times X = 56 \] 6. **Solve for X:** - Rearranging the equation gives: \[ X = \frac{56 \times 100}{0.34} \] - Calculating this: \[ X = \frac{5600}{0.34} \approx 16470.59 \text{ grams} \] 7. **Conclusion:** - The minimum molecular mass of myoglobin is approximately `16470.59 grams/mol`. For practical purposes, we can round this to `16470 grams/mol`. ### Final Answer: The minimum molecular mass of myoglobin is approximately **16470 grams/mol**.
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