In the following reaction, `O_(3)+6I^(-)+6H^(+)rarr 3I_(2)+3H_(2)O` equivalent mass of `O_(3)` (with molecular mass M) is :

Options

A. `(M)/(2)`
B. `(M)/(4)`
C. `(M)/(24)`
D. `(M)/(6)`

Answer

To find the equivalent mass of ozone (O₃) in the given reaction, we can follow these steps:

### Step 1: Understand the Reaction
The reaction provided is:
\[ O_3 + 6I^- + 6H^+ \rightarrow 3I_2 + 3H_2O \]

### Step 2: Define Equivalent Mass
The equivalent mass of a substance is defined as:
\[ \text{Equivalent mass} = \frac{\text{Molecular mass}}{n} \]
where \( n \) is the number of electrons transferred or the change in oxidation state.

### Step 3: Determine the Oxidation States
- In ozone (O₃), the oxidation state of oxygen is 0.
- In water (H₂O), the oxidation state of oxygen is -2.

### Step 4: Calculate the Change in Oxidation State
The change in oxidation state for oxygen in this reaction is:
\[ \text{Change} = 0 \text{ (in O}_3\text{)} - (-2) \text{ (in H}_2\text{O)} = 2 \]

### Step 5: Determine the n Factor
Since the change in oxidation state is 2, the \( n \) factor for ozone in this reaction is also 2.

### Step 6: Calculate the Equivalent Mass
Let the molecular mass of ozone be \( M \). Therefore, the equivalent mass of ozone is:
\[ \text{Equivalent mass of O}_3 = \frac{M}{n} = \frac{M}{2} \]

### Conclusion
The equivalent mass of ozone (O₃) is \( \frac{M}{2} \).

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