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The amount of energy released when 10^(1...

The amount of energy released when `10^(12)` atoms of `Cl` vapours are converted to `Cl^(ɵ)` ions, according to the equation :
`Cl_((g))+e^(-) rarr Cl_((g))^(ɵ)` is `58 xx 10^(-10)J`
Calculate the `Delta_(eg)H^(ɵ)` of `Cl` atom in `kJ mol^(-1)` and `eV "atom"^(-1)`.

Text Solution

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The amount of energy released when one mole `(6.022 xx 10^(23))` atoms of chlorine are converted into ions
`=((57.86 xx 10^(-10)J)xx 6.022 xx 10^(25))/(1 xx 10^(10))=348.4 xx 10^(3)J" mol"^(-1)= 348.4" kJ mol"^(-1)`
Electron gain enthalpy in eV per atom `=(1eV//"atom")/((96.47kJ mol^(-1))xx (-3.48.4 xx kJ mol^(-1)))=-3.61 eV//atom`
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