If molecule `X_(2)` has a triple bond, then X will have the electronic configuratin.

Options

A. `1s ^(2)2s ^(2) 2p^(5)`
B. `1s^(2) 2s^(2)2p^(3)`
C. `1s^(2) 2s ^(1)`
D. `1s^(2)2s^(2)2p^(1)`

Answer

To determine the electronic configuration of the atom X in the molecule \(X_2\) that has a triple bond, we can follow these steps:

### Step 1: Understand the nature of a triple bond
A triple bond consists of three shared pairs of electrons between two atoms. This means that each atom involved in the bond must contribute three electrons to achieve a stable electronic configuration.

### Step 2: Determine the number of valence electrons needed
For an atom to form a triple bond, it typically needs to have a total of 8 electrons in its valence shell to satisfy the octet rule. Since each atom in a triple bond shares three electrons, we can deduce that each atom must have 5 valence electrons initially (5 + 3 = 8).

### Step 3: Identify the possible electronic configurations
Given that X must have 5 valence electrons, we can look at the electronic configurations provided in the options. The electronic configuration that corresponds to 5 valence electrons is that of nitrogen, which is \(1s^2 2s^2 2p^3\).

### Step 4: Analyze the options
1. **Option 1**: 7 valence electrons - This configuration corresponds to halogens, which cannot form triple bonds.
2. **Option 2**: 5 valence electrons - This configuration corresponds to nitrogen, which can form a triple bond.
3. **Option 3**: 1 valence electron - This configuration corresponds to metals, which do not form triple bonds.
4. **Option 4**: 3 valence electrons - This configuration cannot achieve an octet even with a triple bond.

### Step 5: Conclusion
The only configuration that allows for the formation of a triple bond is the one with 5 valence electrons, which is characteristic of nitrogen. Therefore, the electronic configuration of atom X is that of nitrogen.

### Final Answer
The electronic configuration of X when \(X_2\) has a triple bond is \(1s^2 2s^2 2p^3\) (corresponding to nitrogen).

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