20 `dm^(3)` of `SO_(2)` diffuse through a porous partition in 60 s. what volume of `O_(2)` will diffuse under similar conditions in 30 s ?

Explanation

To solve the problem of how much volume of \( O_2 \) will diffuse through a porous partition in 30 seconds, given that 20 dm³ of \( SO_2 \) diffuses in 60 seconds, we can use Graham's law of effusion/diffusion. Here’s the step-by-step solution:

### Step 1: Understand Graham's Law
Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:
\[ \frac{R_1}{R_2} = \frac{M_2^{1/2}}{M_1^{1/2}} \]
where \( R_1 \) and \( R_2 \) are the rates of diffusion of gases 1 and 2, and \( M_1 \) and \( M_2 \) are their molar masses.
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