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Calculate the total and average kinetic energy of `32 g` methane molecules at `27^(@)C`. `(R = 8.314 J K^(-1) mol^(-1))`

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`bar(KE)_(Total)=n xx(3)/(2) RT`
here, `n=(32)/(16)= 2mol`
`therefore bar(KE)_(Total)=((2mol)(8.314JK^(-1)mol^(-1))(300K))/(2)= 7482.6J`
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