Isotherms of carbon dioxide at various temperatures are repersented in figure. Answer the following questions based on this figures.

(i) In which state will `CO_(2)` exist between the points a and b at temperature `T_(1)` ?
(ii) At what point will `CO_(2)` start liquefyinh when temperature is `T_(1)` ?
(iii) At what point will `CO_(2)` be completely liquefued when temperature is `T_(2)` ?
(iv) Will condensation take place when the temperature is `T_(3)` ?
(v) What portion of the isotherm at `T_(1)` represent liquid and gaseous `CO_(2)` at equilibrium ?

Explanation

Average velocity of `CO_(2)` at `T_(1) K = sqrt((8RT_(1))/(π M))`
`implies 9 xx 10^(2) m//sec= sqrt((8RT_(1))/(π (44 xx 10^(-3))))= sqrt(( 8 xx 8.314 xx T_(1))/(3.14(44 xx 10^(-3))))implies T_(1)=1682.5K`
Similarly, Most probable velocity of `CO_(2)` at `T_(2)K = sqrt((2RT_(2))/(M))`
`implies 9 xx 10^(2) m//s= sqrt((2 xx 8.314 xx T_(2))/(44 xx 10^(-3)))implies T_(2)= 2143.37K`