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The ratio between the root mean square v...

The ratio between the root mean square velocity of `H_(2)` at 50 K and that of `O_(2)` at 800 K is:

A

4

B

2

C

1

D

`(1)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`u_(rms)=sqrt((3RT)/(M)), u_("rms") prop sqrt((T)/(M))` `(u_('rms")(H_(2) " " at " " 50 K))/(u_("rms")(O_(2)" " at" " 800 K))= sqrt((50)/(2) xx (32)/(800))=1`
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