A mixture of CO and `CO_(2)` is found to have a density of 1.5 g/L at `30^(@)C` and 740 torr. What is the composition of the mixture. 

Options

A. `CO = 0.35775, CO_(2) = 0.64225`
B. `CO = 0.64225, CO_(2) = 0.3575`
C. `CO = 0.500, CO_(2) = 0.500`
D. `CO = 0.2500, CO_(2) = 0.7500`

Answer

A

Explanation

`because d=(PM)/(RT)implies M=(dRT)/(P)= (1.5 xx 0.0821 xx 303 xx 76)/(74)=38.276`
Let x mole of CO and hence mole of `CO_(2) = (1 – x)`, `38.276 = x xx 28 + (1 – x) 44 implies x = 0.35775`. So `1–x = 0.64225`