If the rate of diffusion of gas X (Molecular mass 64 amu) is 1.4 times the rate of diffusion of gas Y at the same pressure then the molecular mass of gas Y is? 

Explanation

To find the molecular mass of gas Y given that the rate of diffusion of gas X is 1.4 times that of gas Y, we can use Graham's law of diffusion. Here’s a step-by-step solution:

### Step 1: Understand Graham's Law of Diffusion
Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular mass. Mathematically, this can be expressed as:
\[ \frac{r_X}{r_Y} = \sqrt{\frac{M_Y}{M_X}} \]
where \( r_X \) and \( r_Y \) are the rates of diffusion of gases X and Y, and \( M_X \) and \( M_Y \) are their respective molecular masses.
...