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The enthalpy change (Delta H) for the re...

The enthalpy change `(Delta H)` for the reaction
`N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g)`
is `-92.38 kJ` at `298 K`. What is `Delta U` at `298 K`?

Text Solution

AI Generated Solution

To find the internal energy change (ΔU) for the given reaction, we can use the relationship between enthalpy change (ΔH) and internal energy change (ΔU). The formula is: \[ \Delta U = \Delta H - \Delta N_g RT \] Where: - ΔH is the enthalpy change, ...
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