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Compute the Gibbs energy change of the r...

Compute the Gibbs energy change of the reaction at `27^(@)C` for the combustion of methane.
`{:(" "CH_(4)(g)+2O_(2)(g)rarr CO_(2)(g)+2H_(2)O(l)),(Delta_(f)H^(Θ)("in kh mol"^(1))" "-74.8 " "- " "-393.5 " "-285.8),(S_(m)^(Θ)("in J K^(-1)mol"^(-1))" 186 205 214 70"):}`

Text Solution

Verified by Experts

`Delta H^(@)=Delta_(f)H^(@)(CO_(2))+2Delta_(f)H^(@)(H_(2)O)-Delta_(f)H^(@)(CH_(4))`
`=-393.5+2(-285.8)-(-74.8)=-890 kJ mol^(-1)`
`Delta S^(@)=S^(@)(CO_(2))+2S^(@)(H_(2)O)-S^(@)(CH_(4))-2S^(@)(O_(2))`
`=214+2xx70-186-2xx205=-242 JK^(-1)mol^(-1)`
`Delta G^(@)= Delta H^(@)-T Delta S^(@)`
`=-890 - 300xx(-242xx10^(-3))`
`=-890+72.6=-817 kJ mol^(-1)`.
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