Home
Class 12
CHEMISTRY
Calculate the enthalpy of formation of a...

Calculate the enthalpy of formation of acetic acid from the following data.
`CH_3COOH(l) +202 (g) — 2C02 (g) +2H_2O(l), " " Delta H= -207.9` kcal
`C(s) +O_2 (g) —C0_2 (g) . ..(ii) Delta H= -94.48` kcal
`H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), " " Delta H =-68.4` k cal

Text Solution

AI Generated Solution

To calculate the enthalpy of formation of acetic acid (CH₃COOH) from the given reactions, we can use Hess's law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps. ### Step-by-Step Solution: 1. **Write down the reactions and their enthalpy changes:** - Reaction 1: \[ \text{CH}_3\text{COOH}(l) + \text{O}_2(g) \rightarrow 2 \text{CO}_2(g) + 2 \text{H}_2\text{O}(l) \quad \Delta H = -207.9 \text{ kcal} ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|19 Videos

  • CHEMICAL THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|22 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|52 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE)|30 Videos

Similar Questions

Explore conceptually related problems

Calculate the enthalpy of formation of acetic acid from the following data. CH_(3)COOH(l)+2O_(2)(g)rarr 2CO_(2)(g)+2H_(2)O(l), " " Delta H=-207.9 k cal

Calculate the heat of formation of acetic acid form the following data: a. CH_(3)COOH(l) +2O_(2)(g) rarr 2CO_(2)(g) +2H_(2)O(l)DeltaH^(Theta) =- 200.0kcal b. C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.0 kcal c. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH^(Theta) =- 68.0 kcal

Calculate the heat of formation of acetic acid form the following date: a. CH_(3)COOH(l) +2O_(2)(g) rarr 2CO_(2)(g) +2H_(2)O(l)DeltaH^(Theta) =- 200.0kcal b. C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.0 kcal c. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH^(Theta) =- 68.0 kcal

Calculate the heat of formation of methanol (CH_3OH) from thhe following data: CH_3OH(l) + 3/2O_2(g) to CO_2(g) + 2H_2O (l),Delta =-726 kJ C(s) + O_2(g) to CO_2(g) , DeltaH = -394 kJ H_2(g) + 1/2 O_2(g) to H_2O(l) , Delta H = -286 kJ

Calculate the heat of formation of n butane from the following data: a. 2C_(4)H_(10)(g) +13O_(2)(g) rarr 8CO_(2)(g) +10H_(2)O(l), DeltaH = - 5757.2 kJ b. C(s) +O_(2) (g)rarrCO_(2)(g), DeltaH =- 405.4 kJ c. 2H_(2)(g) +O_(2)(g) rarr 2H_(2)O(l), DeltaH =- 572.4 kJ

Calculate the heat of formation of n butane from the followinf data: a. 2C_(4)H_(10)(g) +13O_(2)(g) rarr 8CO_(2)(g) +10H_(2)O(l), DeltaH = - 5757.2 kJ b. C(s) +O_(2) (g)rarrCO_(2)(g), DeltaH =- 405.4 kJ c. 2H_(2)(g) +O_(2)(g) rarr 2H_(2)O(l), DeltaH =- 572.4 kJ

In the reaction 2H_(2)(g) + O_(2)(g) rarr 2H_(2)O (l), " "Delta H = - xkJ

Calculate the heat of formation of glucose from the following data, C(s) + O_2(g) to CO_2(g) , DeltaH =-395.0 kJ H_2(g) + 1/2O_2(g) to H_2O (l) , DeltaH = - 269.4 kJ C_6H_12O_6 (s) + 6O_2(g) to 6CO_2(g) + 6H_2O(l), DeltaH =- 2900 kJ

Calculate the standard enthalpy of formation of CH_(3)OH(l) from the following data: CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1) C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1) H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)

Calculate enthalpy of formation of methane (CH_4) from the following data : (i) C(s) + O_(2)(g) to CO_(2) (g) , Delta_rH^(@) = -393.5 KJ mol^(-1) (ii) H_2(g) + 1/2 O_(2)(g) to H_(2)O(l) , Deta_r H^(@) = -285.5 kJ mol^(-1) (iii) CH_(4)(g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l), Delta_(r)H^(@) = -890.3 kJ mol^(-1) .