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2.2016 gm of acetaldehyde produceed 13.9...

2.2016 gm of acetaldehyde produceed 13.95 Kcal of heat on combustion. The heat of combustion of `CH_(3)CHO` will be

A

279 kcal

B

972 kcal

C

27.9 kcal

D

2.79 kcal

Text Solution

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The correct Answer is:
To find the heat of combustion of acetaldehyde (CH₃CHO), we can follow these steps: ### Step 1: Determine the molar mass of acetaldehyde (CH₃CHO) The molar mass can be calculated as follows: - Carbon (C): 12 g/mol (2 atoms) - Hydrogen (H): 1 g/mol (4 atoms) - Oxygen (O): 16 g/mol (1 atom) Calculating the molar mass: \[ \text{Molar mass of CH}_3\text{CHO} = (2 \times 12) + (4 \times 1) + (1 \times 16) = 24 + 4 + 16 = 44 \text{ g/mol} \] ### Step 2: Calculate the number of moles of acetaldehyde in 2.2016 g Using the formula: \[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \] Substituting the values: \[ \text{Number of moles} = \frac{2.2016 \text{ g}}{44 \text{ g/mol}} \approx 0.05005 \text{ moles} \] ### Step 3: Calculate the heat released per mole of acetaldehyde We know that 2.2016 g of acetaldehyde releases 13.95 kcal of heat. To find the heat released per mole: \[ \text{Heat released per mole} = \frac{\text{Total heat released}}{\text{Number of moles}} \] Substituting the values: \[ \text{Heat released per mole} = \frac{13.95 \text{ kcal}}{0.05005 \text{ moles}} \approx 278.5 \text{ kcal/mol} \] ### Step 4: Round the result We can round the result to a suitable number of significant figures: \[ \text{Heat of combustion of CH}_3\text{CHO} \approx 279 \text{ kcal/mol} \] ### Final Answer The heat of combustion of acetaldehyde (CH₃CHO) is approximately **279 kcal/mol**. ---
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